Belt length for an open two-pulley drive from pulley diameters and shaft centre distance, with the wrap angles.
Page last changed 2026-10-19 · based on n/a — standard engineering relationships, no single governing revision
Open belt: L = 2C + π(D₁ + D₂)/2 + (D₂ − D₁)² ÷ (4C)
Crossed belt: L = 2C + π(D₁ + D₂)/2 + (D₂ + D₁)² ÷ (4C)
Wrap angle on the small pulley: θ = 180° − 2·asin((D₂ − D₁) ÷ 2C)
The belt transmits torque only where it is in contact with the pulley, so the small pulley's wrap angle sets the drive's capacity — and the small pulley always has the smaller wrap, which is why it is the one that slips.
The formula is unforgiving about ratio. With equal pulleys the wrap is 180° on both. With a 2:1 ratio and a centre distance of only twice the large pulley diameter, the small pulley's wrap falls to well under 150°, and the drive's power capacity drops with it. The standard remedy is to increase the centre distance, which is cheaper than changing the belt. As a rule, centre distance should be at least the sum of the two pulley diameters for a 1:1 drive, and more for high ratios.
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| # | Source | Type | Revision / method |
|---|---|---|---|
| [1] | Values computed in your browser | derived | Evaluated locally from the formulas shown on the page. No data leaves the device. |
| Standard | Revision | What it covers on this page |
|---|---|---|
| Formulas as shown on this page | n/a — standard engineering relationships, no single governing revision | every value this calculator produces |
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